2 log 1/4 + 5 log 125 × 3 log 9

==Jawaban==
²log 1/4 + ⁵log 125 x ³log 9
= ²log 2⁻² + ⁵log 5³ x ³log 3²
= -2.²log 2 + 3.⁵log 5 x 2.³log 3
= -2.1 + 3.1 x 2.1
= -2 + 3 x 2
= -2 + 6
= 4

= 2log 2^-2 + 5log 5^3 x 3log 3^2
= -2/1 . 2log 2 + 3/1 . 5log 5 x 2/1 . 3log 3
= -2.1 + 3.1 x 2.1
= -2 + 3 x 2
= 4

Ingat Sifat2 logaritma :
a^mlog b^n = n/m alog b
alog a = 1

Semoga membantu ^_^