Hitunglah nilai dari : 2log (3x - 5) - 2log (x + 1)=1 tolong dibantu

[tex] {}^{2} log(3x - 5) - {}^{2} log(x + 1) = 1 \\ {}^{2} log( \frac{3x - 5}{x + 1} ) = {}^{2} log {2}^{1} \\ \frac{3x - 5}{x + 1} = 2 \\ 3x - 5 = 2x + 2 \\ 3x - 2x = 2 + 5 \\ x = 7[/tex]