1.persamaan garis lurus yang melalui titik (7,-4) dan (9,6) 2.persamaan garis yg melalui titik pankal koordinat dan titik A (-3,4) 3.persamaan gars yg melalui t

1) ( y - y1 ) / ( y2 - y1 ) = ( x - x1 ) / ( x2 - x1 )
( y + 4 ) / ( 6 + 4 ) = ( x - 7 ) / ( 9 - 7 )
( y + 4 ) / 10 = ( x - 7 ) / 2
2 ( y + 4 ) = 10 ( x - 7 )
2y + 8 = 10x - 70
2y - 10x = - 70 - 8
2y - 10x = - 78
disederhanakan
y - 5x = - 39

2) ( y - y1 ) / ( y2 - y1 ) = ( x - x1 ) / ( x2 - x1 )
( y - 0 ) / ( 4 - 0 ) = ( x - 0 ) / ( - 3 - 0 )
y / 4 = x / - 3
- 3y = 4x
- 3y - 4x = 0

3) 3x - 2y - 6 = 0
- 2y = - 3x + 6
m = -3/-2
m = 3/2
sejajar m1 = m2 = 3/2
pers garis
y - y1 = m ( x - x1 )
y - 5 = 3/2 ( x + 2 )
y = 3/2 x + 3 + 5
y = 3/2 x + 8 ( dikali 2 )
2y = 3x + 16
2y - 3x = 16

4) 4y - 2x = 8
4y = 2x + 8
m = 2/4
m = ½
gradien saling tegak lurus
m1 . m2 = - 1
½ • m2 = - 1
m2 = - 2

5) (y - y1 ) / ( y2 - y1 ) = ( x - x1 ) / ( x2 - x1 )
( y - 2 ) / ( - 1 - 2 ) = ( x - 5 ) / ( - 1 - 5 )
( y - 2 ) / - 3 = ( x - 5 ) / - 6
- 6 ( y - 2 ) = - 3 ( x - 5 )
- 6y + 12 = - 3x + 15
- 6y + 3x = 15 - 12
- 6y + 3x = 3
disederhanakan
- 2y + x = 1
- 2y = - x + 1
m = -1/-2
m = ½
sejajar m1 = m2 = ½
pers garis
y - y1 = m ( x - x1 )
y - 3 = ½ ( x + 2 )
y = ½ x + 1 + 3
y = ½ x + 4 ( dikali 2 )
2y = x + 8
2y - x = 8