hitung panjang AC dan AD

MAPEL = MATEMATIKA
KELAS = 9
BAB = KESEBANGUNAN

diketahui =
CB = 20 cm
CD = 12 cm
DB = 16 cm

ditanya =
panjang AC & AD??


[tex] {cd}^{2} = ad \times bd \\ 1 {2}^{2} = ad \times 16 \\ 144 = 16ad \\ \: \: ad = \frac{144}{16} \\ \: \: ad = 9[/tex]
jadi panjang ad = 9cm


[tex]ac = \sqrt{ad \times ab } \\ ac = \sqrt{9 \times (9 + 16) } \\ ac = \sqrt{9 \times 25 } \\ ac = \sqrt{225 } \\ ac = 15[/tex]
jadi panjang ac = 15cm

semoga membantu