sebuah kerucut diamaternya 10cm dan volumenya 314cm³ jika π=3,14 hitunglah a.tingginya b.luas selimutnya TOLONG DIJAWAB DONG

Mapel : Matematika
Bab : BRSL

d = 10 cm
r = 5 cm

V = phi × r^2 × t
314 = 3,14 × 5 × 5 × t
314 = 78,5 × t
314/78,5 = t
4 = t

a) t = 4 cm

[tex]s = \sqrt{r ^{2} + t ^{2} } [/tex]
[tex]s = \sqrt{5 ^{2} + 4 ^{2} } [/tex]
[tex]s = \sqrt{25 + 16} [/tex]
[tex]s = \sqrt{41} [/tex]

[tex]s = 6.403 \: cm[/tex]

b)

L selimut = phi × r × s
L Selimut = 3,14 × 5 × 6,403
L Selimut = 100,5271 cm^2