diketahui ^ -5 log 3 = a dan ^3 log 4 = b ^4 log 15 =

[tex] {}^{ - 5} log3 = a \\ {}^{3} log4 = b \\ \\ {}^{4} log15 \\ {}^{4} log(5 \times 3) \\ {}^{4} log5 + {}^{4} log3 \\ \frac{ {}^{3} log5 }{ {}^{3} log4 } + {}^{4} log3 \\ \frac{ \frac{1}{ {}^{5 log3 } } }{ {}^{3} log4 } + \frac{1}{ {}^{3} log4 } \\ \frac{ \frac{1}{a} }{b} + \frac{1}{b} \\ \frac{1}{a} \times \frac{1}{b} + \frac{1}{b} \\ \frac{1}{ab} + \frac{1}{b} \\ \frac{b + ab}{a {b}^{2} } \\ \frac{b(1 + a)}{b.ab} \\ \frac{1 + a}{ab} [/tex]