persamaan garis lurus yang melalui (3, -6) dan sejajar garis 5x - 4y = 7 adalah.. a) 4x + 5y = -18 b) 4x + 5y = 28 c) 5x - 4y = -9 d) 5x - 4y = 39 minta tolong
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Pertanyaan
persamaan garis lurus yang melalui (3, -6) dan sejajar garis 5x - 4y = 7 adalah..
a) 4x + 5y = -18
b) 4x + 5y = 28
c) 5x - 4y = -9
d) 5x - 4y = 39
minta tolong yaa!!!
a) 4x + 5y = -18
b) 4x + 5y = 28
c) 5x - 4y = -9
d) 5x - 4y = 39
minta tolong yaa!!!
1 Jawaban
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1. Jawaban Hanifahwh
5x - 4y = 7
m1 = -a/b
m1 = -5/-4 → 5/4
m1 = m2 = 5/4 (Sejajar)
(3,-6) → (x1 , y1)
Jadi persamaan garis nya :
y - y1 = m2 (x - x1)
y - (-6) = 5/4 (x - 3)
y + 6 = 5/4x - 15/4
_______________ x 4
4 (y + 6) = 5x - 15
4y + 24 = 5x - 15
24 + 15 = 5x - 4y
39 = 5x - 4y
→ 5x - 4y = 39 (D)