Turunan pertama dari fungsi2: a. Y= (2x² + x) (2 + 2x^-1) b. Y= ✓2x + 2 ✓x
Matematika
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Pertanyaan
Turunan pertama dari fungsi2:
a. Y= (2x² + x) (2 + 2x^-1)
b. Y= ✓2x + 2 ✓x
a. Y= (2x² + x) (2 + 2x^-1)
b. Y= ✓2x + 2 ✓x
1 Jawaban
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1. Jawaban Dickydhar23
a. Y = (2x² + x) (2 + 2x^-1)
Rumus = U'V + VU'
= (4x + 1)(2 + 2x^-1) + (2x² + x)(-2x^-2)
= (8x + 8x^1-1 + 2 + 2x^-1) + (-4x^2+-2 + -2x^1-2)
= (8x + 8 + 2 + 2x^-1) + (-4 + -2x^-1)
= (8x + 2x^-1 + -2x^-1 + 8 + 2 - 4)
= (8x + 0 + 6)
= 8x + 6
b. Y = √2x + 2√x
= (2x)^1/2 + 2(x)^1/2
= 1/2(2x)^-1/2 + (x)^-1/2
= 1/2(1/2x^1/2) + 1/x^1/2
= 1/2(1/√2x) + 1/√x