Matematika

Pertanyaan


[tex]2 \times \frac{1}{2} (2x - 3) + 6 = 15 - \frac{x}{2} [/tex]
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  • [tex]2 \times \frac{1}{2} (2x - 3) + 6 = 15 - \frac{x}{2} \\ 1(2x - 3) + 6 = 15 - \frac{x}{2} \\ 2x - 3 = 15 - 6 - \frac{x}{2} \\ 2x - 3 = 9 - \frac{x}{2} \\ 4x - 6 = 18 - x \\ 4x + x = 18 + 6 \\ 5x = 24 \\ x = \frac{24}{5} [/tex]

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