Tentukan persamaan garis yg melalui titik (3,5) dan (7,11)

y-y1 per y2-y1 = x-x1 per x2-x1
y-5 per 11-5 = x-3 per 7-3
y-5 per 6 = x-3 per 4 (dikalikan silang)
(y-5).4 = (x-3).6
4y-20 = 6x-18
4y-6x = 20-18
4y-6x = 2 (dibagi 2 semua)
2y-3x =0.