tolong bantuin dongg

AG = 48 cm
AB = 10 cm
AC = AG/3 = 48/3 = 16 cm
Alas segitiga ABC = 16/2 = 8 cm
KJ = 8 cm x 4 = 32 cm
tinggi trapesium = 6 cm x 2 = 12 cm
tinggi segitiga ABC^2 = AB^2 - 1/2 alas ABC^2 = (10 x 10) - (8 x 8) = 36 cm
tinggi segitiga ABC = [tex] \sqrt{36} [/tex]=6 cm
Luas segitiga ketiga segitiga =3 x ( 1/2 x alas x tinggi )
= 3 x (0,5 x 16 cm x 6 cm) = 48 cm^2 x 3 = 144 cm
luas trapesium = [(KJ + AG) x tinggi]/2 = [(32 + 48) x 12 cm] / 2 = (80 cm x 12 cm) / 2 = 40 cm x 12 cm = 480 cm
luas daerah yang terarsir = 480 cm - 144 cm = 336 cm