F'(x) = 3x+7, f(2) = 20 tentukan constantanya
Matematika
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Pertanyaan
F'(x) = 3x+7, f(2) = 20 tentukan constantanya
1 Jawaban
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1. Jawaban Anonyme
Kelas 12 Matematika
Bab Integral
f' (x) = 3x + 7
∫ (3x + 7) dx
= (3/2) x² + 7x + C
f(x) = (3/2) x² + 7x + C
f(2) = 20
(3/2) . 2² + 7 . 2 + C = 20
(3/2) . 4 + 14 + C = 20
6 + 14 + C = 20
C = 20 - 20
C = 0