suatu kerucut jari jarinya 7 cm dan tingginya 24 cm. jika π =22/7 maka luas selimut kerucut adalah, tolong bantu jawab yah

r= 7 cm
t= 24 cm
Ditanya= LS?

S²= r²+t²
S²= 24²+7²
S²= 576+49
S= √625
S= 25 cm

LS= πrs
LS= 22/7 x 7 x 25
LS= 22 x 25
LS= 550 cm²

Hopefully this is the best for you, stay focus and be the best, Buddy :)