tolong kerjain nomor 2

f(1)=3×1+4
f(1)=3+4
f(1)=7

F(2)=3×2+4
=6+4
=10
f(3)=3×3+4
=9+4
=13
f(4)=3×4+4
=12+4
=16
daerah hasil(7,10,13,16)

f (1) = 3 × 1 + 4
f (1) = 3 +4
f (1) = 7

f (2) = 3 × 2 + 4
f (2) = 6 + 4
f (2) = 10

f (3) = 3 × 3 + 4
f (3) = 9 + 4
f (3) = 13

f (4) = 3 × 4 + 4
f (4) = 12 + 4
f (4) = 16

a. Daerah hasil = {7, 10, 13, 16}
b. Himpunan pasangan berurutan {(1,7), (2,10), (3,13), (4,16)}