tentukan hasil perhitungan dari (2+2)x3+10-(4+6)x2-2

(2+2)x3+10-(4+6)x2-2
4x3+10-10x2-2
12+10-20-2
22-20-2
2-2=0

[tex](2 + 2) \times 3 + 10 - (4 + 6) \times 2 - 2 \: \\ = 4 \times 3 + 10 - 10 \times 2 - 2 \\ = 12 + 10 - 20 - 2 \\ = 22 - 20 - 2 \\ = 2 - 2 = 0[/tex]