f^(-1) (x)=(x-1)/5 dan g^(-1) (x)=(3-x)/2,maka (F°G)

jawab

f⁻¹ (x) = (x -1) /5
x - 1 = 5y
x = 5y  + 1
f(x) = 5x + 1

g⁻¹(x) = (3-x)/2
2y = 3 - x
x = 3 - 2y
g(x) = 3 - 2x

fog(x) =  f{ g(x)}
= f(3-2x)
= 5 (3 -2x)  +1
= 15 - 10x + 1
= 16 - 10 x