hitunglah titik larut glikol 20% masa!(mr=62: kf=1.86 c/m)
Kimia
Mangayu7312
Pertanyaan
hitunglah titik larut glikol 20% masa!(mr=62: kf=1.86 c/m)
1 Jawaban
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1. Jawaban bisma7
∆tf=m.kf=20/62 .1000/80.1,86=7,5
Tf=-7,5