persamaan garis yg melalui titik A(0,3) dan B(2,-5) adalah... pake cara yak

m= -5-3/2-0
= -4
y= mx-b
y= -4x-b (2,-5)
-5= -8-b
-3=b
y=-4x-3
4x+y=-3

bismillah

[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} [/tex]
[tex] \frac{y - 3}{ - 5 - 3} = \frac{x - 0}{2 - 0} [/tex]
[tex] \frac{y - 3}{ - 8} = \frac{x}{2} [/tex]
2(y-3) = -8x
2y - 6 = -8x
sederhana
y-3 = -4x
atau
4x+y = 3

semoga bermanfaat
terus berlatih