diket : 90 derajat< x< 180 derajat tan x = minus akar 12 ditanya : rasio trigonometri lainnya!!!

tan x = -√12 = [tex] \frac{\sqrt{12} }{-1} [/tex]
tan x = [tex] \frac{y}{x} [/tex]
y = √12
x = -1
r = [tex] \sqrt{(-1)^{2} + ( \sqrt{12})^{2} } = \sqrt{1 + 12} = \sqrt{13} [/tex]

sin x = [tex] \frac{y}{r} [/tex] = [tex] \frac{ \sqrt{12} }{ \sqrt{13} } [/tex]

cos x = [tex] \frac{x}{r} [/tex] = [tex] \frac{-1}{ \sqrt{13} } [/tex]