hit ph dari larutan a) KoH 0,1M b) H2so4 0,05M

a [OH-] = Valensi x M
= 1 x 0.1
= 0.1

poh = -log [OH-]
=-log 0,1
= 1

ph = 14-poh = 13

b. [H+] = valensi x M
= 2 x 0.05
= 0.1

ph = - log H+
= 1