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Matematika
aulialinda
Pertanyaan
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1 Jawaban
-
1. Jawaban fufutiensov2brh
No 1
4a ^ -2 x 2a = 1/(4a)^2 × 2a = 1/16a^2 × 2a = 2a / 16a^2
= 1/8a (B)
No 2
4^2 × 32 ^3/5 × 128 ^ -3/7
= 2 ^ 4 × 2 ^ 15/5 × 2^ -21/7
= 2^4 × 2^3 × 2^-3
= 2^(4+3+-3)
=2^4 (B)
No 3
5 ^ 4+x = 3125
5^ 4+x = 5^5
4+x = 5
X = 5 -4
x= 1 (E)
No 4
x/y^-3 + y / x^-2 = XY^3 + X^2Y
= XY (Y^2 + X) (B)
No 5
(a ^-1 b^2) ^3 / (a^-9 b^3) = a^-3 b^6 / a^-9 b^3
= a^ -3 - -9 b^ 6-3
= a ^ -3 +9 b ^ 3
= a^6 b ^3 (B)
No 6
(16/81 p^8 q^12) : (1/81 p^8 q^8)
= 16 q^4 (A)