Tentukan persamaan garis melalui titik P(4,-3) dan Q(-2,5)

Kelas 8 Matematika
Bab Persamaan Garis

(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y + 3) / (5 + 3) = (x - 4) / (-2 - 4)
(y + 3)/8 = (x - 4)/(-6)
(-6) (y + 3) = 8 (x - 4)
-6y - 18 = 8x - 32
8x + 6y = 32 - 18
8x + 6y = 14
4x + 3y = 7

[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1 } \\ \frac{y - ( - 3)}{5 - ( - 3)} = \frac{x - 4}{ (- 2) - 4} \\ - 6(y + 3) = 8(x - 4) \\ - 6y - 18 = 8x - 32 \\ - 6y = 8x - 32 + 18 \\ y = - \frac{8}{6} x + \frac{14}{6} [/tex]