9^(3x+2)=(1)/(81^(2x-5))

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[tex]9 {}^{3x + 2} = ( \frac{1}{81}) {}^{2x - 5} \\ (3 {}^{2} ) {}^{3x + 2} = (3 {}^{ - 4} ) {}^{2x - 5 } \\ 3 {}^{6x + 4} = {3}^{ - 8x + 20 } \\ 6x + 4 = - 8x + 20 \\ 14x = 16 \\ x = \frac{16}{14} \\ x = \frac{8}{7} \\ x = 1 \frac{1}{7} [/tex]