Dik: C – C = 350 kJ C – H = 415 kJ C = O = 745 kJ O – H = 464 kJ O = O = 498 kJ Dit: perubahan entalpi pada reaksi: CH3 – CH3 + 31/2 O = O → 2O = C = O + 3H –
Kimia
antariksa29
Pertanyaan
Dik: C – C = 350 kJ
C – H = 415 kJ
C = O = 745 kJ
O – H = 464 kJ
O = O = 498 kJ
Dit: perubahan entalpi pada reaksi: CH3 – CH3 + 31/2 O = O → 2O = C = O + 3H – O – H
C – H = 415 kJ
C = O = 745 kJ
O – H = 464 kJ
O = O = 498 kJ
Dit: perubahan entalpi pada reaksi: CH3 – CH3 + 31/2 O = O → 2O = C = O + 3H – O – H
1 Jawaban
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1. Jawaban primaalisa99
delta H= (3 E C=O + 4 E H-O) - ( 6 E C- H + 2 E C- C + 3,5 E O=O )
=(3×745 + 4×464) - ( 6× 415 + 2× 350 + 3,5×498)
= (2235+1856)-(2490+700+1743)
=4091-4933
=-842