Matematika

Pertanyaan

nomor 10,12dan 13 yg susuah itu tolong bantu.
nomor 10,12dan 13 yg susuah itu tolong bantu.

2 Jawaban

  • jawab

    10)

    3²ˣ⁺¹  - 3. 3ˣ - 6 = 0
    3. (3ˣ)² - 3. (3ˣ) - 6 = 0 ..}bagi 3
    (3ˣ)² - (3ˣ)  - 2 = 0
    misalkan 3ˣ = a  atau x = ³log a , dengan a > 0
    a² - a  - 2= 0
    (a - 2)(a +1) = 0
    a = 2 atau a = -1 (TM)

    untuk a = 2  maka x = ³log a
    x = ³log 2

    12)
    a^(-1/3) . b^(1/2) =
    a= 8 dan b  = 9
    = (8)^(-1/3) . (9)^(1/2)
    = (2^3)^(-1/3)  (3^2)^(1/2)
    = 2^-1 . 3^1
    = 3/2
    ^ pangkat

    13.
    (a)

    (a³ b ) /b .  (4a³ b)/ a =
    = a³ . 4a²b
    = 4 a⁵ b

    (b)

    (b⁻¹ - a⁻¹)/(b a⁻¹  - a b⁻¹) ..kalikan  ab/ab
    = ab (b⁻¹ - a⁻¹) / (ab)( b a⁻¹ - a b⁻¹)
    = (a - b)/(b² - a²)
    = (a - b ) /  - (a² - b²)
    = (a - b) / -  (a + b )(a - b)
    =  1/ -(a +b)
    = 1/ (-a - b)

  • 12. a^(-1/3) . b^(1/2) =
    a= 8 dan b = 9
    = (8)^(-1/3) . (9)^(1/2)
    = (2^3)^(-1/3) (3^2)^(1/2)
    = 2^-1 . 3^1
    = 3/2

    13.
    (a) (a³ b ) /b . (4a³ b)/ a =
    = a³ . 4a²b
    = 4 a⁵ b

    (b) (b^-1 - a^-1)/(b a^-1 - a b^-1)
    = ab (b^-1 - a^-1) / (ab)( b a^-1 - a b^-1)
    = (a - b)/(b² - a²)
    = (a - b ) / - (a² - b²)
    = (a - b) / - (a + b )(a - b)
    = 1/ -(a +b)
    = 1/ (-a - b)

    maaf nomor 10 gak tau

    #semogamembantu

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