nomor 10,12dan 13 yg susuah itu tolong bantu.
Matematika
wizarg
Pertanyaan
nomor 10,12dan 13 yg susuah itu tolong bantu.
2 Jawaban
-
1. Jawaban Anonyme
jawab
10)
3²ˣ⁺¹ - 3. 3ˣ - 6 = 0
3. (3ˣ)² - 3. (3ˣ) - 6 = 0 ..}bagi 3
(3ˣ)² - (3ˣ) - 2 = 0
misalkan 3ˣ = a atau x = ³log a , dengan a > 0
a² - a - 2= 0
(a - 2)(a +1) = 0
a = 2 atau a = -1 (TM)
untuk a = 2 maka x = ³log a
x = ³log 2
12)
a^(-1/3) . b^(1/2) =
a= 8 dan b = 9
= (8)^(-1/3) . (9)^(1/2)
= (2^3)^(-1/3) (3^2)^(1/2)
= 2^-1 . 3^1
= 3/2
^ pangkat
13.
(a)
(a³ b ) /b . (4a³ b)/ a =
= a³ . 4a²b
= 4 a⁵ b
(b)
(b⁻¹ - a⁻¹)/(b a⁻¹ - a b⁻¹) ..kalikan ab/ab
= ab (b⁻¹ - a⁻¹) / (ab)( b a⁻¹ - a b⁻¹)
= (a - b)/(b² - a²)
= (a - b ) / - (a² - b²)
= (a - b) / - (a + b )(a - b)
= 1/ -(a +b)
= 1/ (-a - b) -
2. Jawaban Jillaja
12. a^(-1/3) . b^(1/2) =
a= 8 dan b = 9
= (8)^(-1/3) . (9)^(1/2)
= (2^3)^(-1/3) (3^2)^(1/2)
= 2^-1 . 3^1
= 3/2
13.
(a) (a³ b ) /b . (4a³ b)/ a =
= a³ . 4a²b
= 4 a⁵ b
(b) (b^-1 - a^-1)/(b a^-1 - a b^-1)
= ab (b^-1 - a^-1) / (ab)( b a^-1 - a b^-1)
= (a - b)/(b² - a²)
= (a - b ) / - (a² - b²)
= (a - b) / - (a + b )(a - b)
= 1/ -(a +b)
= 1/ (-a - b)
maaf nomor 10 gak tau
#semogamembantu
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