[tex] \binom{1}{49 {}^{x + 3} } = \sqrt[3]{49 {}^{3x - 6} } [/tex]
Matematika
Luthfi0891
Pertanyaan
[tex] \binom{1}{49 {}^{x + 3} } = \sqrt[3]{49 {}^{3x - 6} } [/tex]
1 Jawaban
-
1. Jawaban AfarizkaFalisyah
[tex]7^{ - 2x - 6} = {7}^{ \frac{2(3x6)}{3} } \\ {7}^{ - 2x - 6} = {7}^{ \frac{2 \times 3(x - 2)}{3} } \\ {7}^{ - 2x - 6} = {7}^{2(x - 2)} \\ {7}^{ - 2x - 6} = {7}^{2x - 4} \\ - 2x - 6 = 2x - 4 \\ - 2x - 2x = - 4 + 6 \\ - 4x = 2 \\ x = - \frac{1}{2} [/tex]sorry klo salah