Matematika

Pertanyaan


[tex] \binom{1}{49 {}^{x + 3} } = \sqrt[3]{49 {}^{3x - 6} } [/tex]

1 Jawaban


  • [tex]7^{ - 2x - 6} = {7}^{ \frac{2(3x6)}{3} } \\ {7}^{ - 2x - 6} = {7}^{ \frac{2 \times 3(x - 2)}{3} } \\ {7}^{ - 2x - 6} = {7}^{2(x - 2)} \\ {7}^{ - 2x - 6} = {7}^{2x - 4} \\ - 2x - 6 = 2x - 4 \\ - 2x - 2x = - 4 + 6 \\ - 4x = 2 \\ x = - \frac{1}{2} [/tex]sorry klo salah

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