nilai x yang memenuhi persamaan |x-3|²-4|x-3|-12=0 adalah...

Misal |x-3| = a

a² - 4a -12 = 0
(a - 6)(a + 2) = 0

a = 6
|x - 3| = 6
x -3 = 6
x = 9

x - 3 = -6
x = -3

a = -2
|x-3| = -2
tdk memenuhi

hp = {-3,9}