Matematika

Pertanyaan

Soal turunan y=sin x tan(x2+1)

1 Jawaban

  • y = sinx . tan(x² + 1)

    u = sinx
    u' = cosx

    v = tan(x² + 1)
    v' = 2x . sec²(x² + 1)

    y' = u v' + u' v
    y' =  sinx . 2x . sec²(x² + 1) + cosx . tan(x² + 1)
    y' = 2x . sinx . sec²(x² + 1) + cosx . tan(x² + 1)

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