mohon bantuan guys,remed dikumpul bsk

[tex]pertama\ proyeksikan\ semua\ gaya\ ke\ arah\ horizontal,\\ U\ horizontal\ =U.cos\theta\\U\ horizontal\ = 10.cos45\\U\ horizontal\ = 10.\frac{1}{2}.\sqrt2\\ U\ horizontal=5\sqrt2\ N.\\ \\ V\ horizontal=V.cos\theta\\ V\ horizontal=10.cos45\\ V\ horizontal=10.\frac{1}{2}.\sqrt2\\ V\ horizontal=5\sqrt2\ N.\\ \\ Resultan\ gaya\ pada\ sumbu\ horizontal\ atau\ sumbu\ x\\ U+V-W\\ 5\sqrt2+5\sqrt2-10\\ 10\sqrt2-20\\ 10.1,4-20\\ 14-20\\ -6\ Newton=6\ Newton\ arah\ ke\ kanan\ sumbu\ x.(A)[/tex]