Nilai x dari 3^x+3=√3^x+2

3^x+3 = √3^x+2
3^x+3 = (3^x+2)^1/2
3^x+3 = 3^x/2 + 1
x + 3 = x/2 + 1
2x + 6 = x + 2
2x - x = 2 - 6
x = -4

[tex]3 {}^{x + 3} = \sqrt{3 {}^{x + 2} } \\ \sqrt{3 {}^{x + 2} } = 3 {}^{x + 3 } \\ 3 {}^{x + 2} = 3 {}^{(x + 3) \times 2} \\ \\ karna \: basis \: sdh \: sama \: maka \: tinggal \: hitung \: pangkatnya \: saja \\ sehingga \\ x + 2 = (x + 3) \times 2 \\ x + 2 = 2x + 6 \\ x - 2x = 6 - 2 \\ - x = 4 \\ x = - 4[/tex]