tolong kerjakan no.2 dan 3
Matematika
sabitacandra
Pertanyaan
tolong kerjakan no.2 dan 3
2 Jawaban
-
1. Jawaban nandazn17
2. K = 14 + 8 + 20 + 10
= 52
L1= p × l
= 14 × 8
= 112 cm²
L2= 1/2 × a × t
= 1/2 × 6 × 8
= 24 cm²
L = L1 + L2
= 112 cm² + 24 cm²
= 136 cm²
Maaf hanya bisa no 2 -
2. Jawaban RaNiiDwi
1. L1 = 1/2 x a x t
= 1/2 x 6 x 8
= 24
L2 = P x L
= 14 x 8
= 112
luas bangun = L1 + L2
= 24 + 112 = 136 cm²
2. L1 = P x L
= 30 x 21
= 630
L2 = 1/2 x [tex] \pi [/tex]r²
= 1/2 x 3,14 x 10,5²
= 1/2 x 346,185
= 173,0925
luas = L1 - L2
= 630 - 173,0925
= 456, 9075 cm²
keliling;
K1 = 2 ( p + l )
= 2 ( 30 + 21 )
= 102 cm
K2 = 1/2 x 2[tex] \pi [/tex]r
= 1/2 x 2 x 3,14 x 10,5
= 32,97
K bangun = K1 - K2
= 102 - 32,97
= 69,03 cm