nilai x yg memenuhi persamaan [tex] {3}^{2x - 4 } = \frac{1}{3} \sqrt{243} [/tex] pliisss bantu aku dong..

3^ 2x - 4 = 1/3 √243

untuk √243 = 9√3

3^2x - 4 = 3-¹ (3²) 3^ ½

[tex] {3}^{2x - 4} = {3}^{ - 1} \: {3}^{2} \: {3}^{ \frac{1}{2} } \\ 3 {}^{2x - 4} = 3 { }^{ - 1 + 2 + \frac{1}{2} } \\ [/tex]
karena basis sudah sama maka hitung pangkatnya

2x - 4 = -1 + 2 + ½
2x = 3/2 + 4
2x = 3/2 + (8/2)
2x = 11/2
x = 11/2 × 1/2
x = 11 / 4