persamaan garis melalui titik (-6,3)dan tegak lurus garis 2x + 3y=0

m1=2
m1.m2=-1
2.m2=-1
m2=-1/2

y-y1=m2(x-x1)
y-3 =-1/2(x-(-6))
y-3 =-1/2× x (-6)
y=-1/2× x (-6)+3
y=-1/2× +-9