Nilai x yang memenuhi sistem persamaan y = 4x^2 - 4x + 3, y = 3x adalah

y = 4x²- 4x + 3
y = 3x

Maka
4x²-4x+3 = 3x
4x²-4x-3x+3 = 0
4x²-7x+3 = 0
(4x-3) (x-1) = 0

4x-3 = 0
4x = 3
x = 3/4

x-1 = 0
x = 1

y=4x²-4×+3
y=3×

=4ײ- 3×
= 4×+3
------------(+)
×=8²+6
×=64+6
×=70