Matematika

Pertanyaan

Nilai dari 8 log 1/5 dikali 5 log 1/27 dikurang 2 log 24

1 Jawaban

  • 8log 1/5 × 5log 1/27 - 2log 24
    = l(og 1/5)/log 8 × log (1/27)/log 5 - 2log 24
    = (log 5^-1)/(log 2^3) × (log 3^-3)/(log 5) -2log 24
    =(-log 5)/(3.log 2)× (-3log 3)/(log 5) -2log 24
    =3.log 3 /3.log 2 -2log 24
    = 2log 3 -2log 24
    = 2log (3/24)
    = 2log (1/8)
    = 2log 2^-3
    = -3

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