Matematika

Pertanyaan

Jika a = 0,333... dan b = √72+√72+√72+√72+... Maka a log b =
a. 1
b. 1/2
c. -2
d. 2
e. 1
Jika a = 0,333... dan b = √72+√72+√72+√72+... Maka a log b = a. 1 b. 1/2 c. -2 d. 2 e. 1

0 Comment.

1 Jawaban

  • a = 0,333...
    10a = 3,333...
    10a - a = 3,333.. - 0,333...
    9a = 3
    a = 3/9 = 1/3 = 3^-1

    b = √(72 + √(72 + √(...
    b²:= 72 + b
    b² - b + 72 = 0
    (b - 9)(b + 8) = 0
    b = 9

    ^alog b = ^(3^-1)log 9
    ^alog b = ^(3^-1)log 3^2
    ^alog b = 2/-1 = -2

Pertanyaan Lainnya