diketahui fungsi f(x)=√4+x dan g(x)=X2+4 tentukan (fog) (x) (gog) (x) (fog)-1 (x) (Gof)-1 (x) X2 itu bukan X2 tapi x pangkat 2 terimakasih yang bantu

fog (x) = √4+(x²+4)
= 2 +x +2
= x + 4

gof (x) = (√4+x)² + 4
= 4+x+4
= x + 8

maaf jika salah ya

[tex]f(x)= \sqrt{4} +x \\ g(x)= x^{2} +4 \\ fog(x)= \sqrt{4}+ x^{2} +4 \\ fog(x)=2+ x^{2}+4 \\ fog(x)= x^{2} +6 \\ \\ gog(x)=( x^{2}+4)^{2} +4 \\ gog(x)= x^{4} +4 x^{2} +4 x^{2} +16 \\ gog(x)= x^{4}+8 x^{2} +16 \\ \\ (fog)^{-1} (x)= x^{2} +6 \\y= x^{2} +6 \\ y-6= x^{2} \\ x= \sqrt{y-6} \\(fog)^{-1}= \sqrt{x-6} [/tex]
[tex] \\ gof(x)= ( \sqrt{4}+x) ^{2}+4 \\ gof(x)= (2+x)^{2}+4 \\ gof(x)=4+2x+2x+ x^{2} +4 \\ gof(x)=4+4x+ x^{2} +4 \\ gof(x)=8+4x+ x^{2} \\ (gof)^{-1} (x)= (2+x)^{2}+4 \\y= (2+x)^{2}+4 \\ y-4= (2+x)^{2} \\ \sqrt{y-4} =2+x \\ x= \sqrt{y-4}-2 \\ (gof)^{-1} (x)= \sqrt{x-4}-2 [/tex]

Maaf kalo salah, semoga membantu