Matematika

Pertanyaan

[tex] \sqrt{75} + \frac{1}{4} \sqrt{48} - \sqrt{27} + \sqrt{6} X \sqrt{2} [/tex] berapa?
X = kaliĀ 

1 Jawaban

  • [tex] \sqrt{25.3} + \frac{1}{4} \sqrt{16.3} - \sqrt{9.3} + \sqrt{12} \\ 5 \sqrt{3} + \frac{4}{4} \sqrt{3} -3\sqrt{3} + \sqrt{4.3} \\ 5 \sqrt{3} + \frac{4}{4} \sqrt{3} -3\sqrt{3} + 2\sqrt{3} \\ (5+1-3+2)\sqrt{3} \\ 5\sqrt{3}[/tex]

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